Voltage Drop Calculation for 3-Phase Systems

Three-Phase Voltage Drop Formula

VD = √3 × L × I × R ÷ 1000

Worked Example: 3-Phase 208V Circuit

Scenario: 208V 3-phase, 40A load, 150 ft run, 8 AWG copper.

Step 1: R for 8 AWG copper = 0.778 ohms/1000ft (NEC Table 9, AC, 75°C)

Step 2: VD = 1.732 × 150 × 40 × 0.778 ÷ 1000 = 8.09V

Step 3: Line-to-line voltage drop = 8.09V. Line-to-neutral = 8.09 ÷ √3 = 4.67V

Step 4: %VD = 8.09 ÷ 208 × 100 = 3.89% (exceeds 3%)

Fix: Use 6 AWG (R=0.491): VD = 1.732 × 150 × 40 × 0.491 ÷ 1000 = 5.10V = 2.45% ✓

Single-Phase vs 3-Phase Comparison

FactorSingle-Phase (240V)Three-Phase (208V)
Power at 40A9,600 W14,400 W
Wire neededSame gaugeSame gauge
VD factor2 × L × I × R√3 × L × I × R
VD for 150ft, 8 AWG, 40A9.34V (3.9%)8.09V (3.9%)
Power per volt of drop1,028 W/V1,780 W/V

Frequently Asked Questions

How do you calculate voltage drop for 3-phase?

VD = √3 × L × I × R ÷ 1000. Where √3 ≈ 1.732, L = length (ft), I = current per phase (amps), R = resistance per 1000ft (NEC Table 9). For balanced loads, calculate for one phase.

What is the difference between single-phase and 3-phase voltage drop?

Single-phase: VD = 2 × L × I × R ÷ 1000 (factor of 2 for hot + neutral round trip). Three-phase: VD = √3 × L × I × R ÷ 1000 (factor of √3 because return path is shared). Three-phase has ~13% less voltage drop for the same power.

When should I use 3-phase power?

Three-phase is used for: motors >5 HP, large commercial loads, industrial equipment, and when voltage drop is a concern on long runs. Three-phase delivers more power with less copper and lower voltage drop.

Disclaimer: For preliminary design only. Verify against local codes and professional engineering requirements.